DO U GET IT ?? ( cas i dont hahah)
now MOVING ON.
are u ready?
so lets start by knowing the basics.
what is the formula of percent yeild?
| hmmmmmm? (: |
percent yield: is the ratio of # of product obtained to # of product expected by calculation, expressed as %.
Here's an example:
Q: What is the % yield of water if 138 g H2O is produced from 16g H2 and excess O2?
STEP 1: Write the balanced chemical equation
2H2 + O2 ---> 2H2O
STEP 2: Determine the actual and theoretical yield. Actual is given and theoretical is calculated.
#g H2O = 16g H2 x 1 mol H2 x 2 mole H2O x 18.02 H2O = 143 g
2.02 g H2 2 mole H2 1 mol H2O
STEP 3: Calculate percent yield.
13g H2O x 100% = 96.
143 g H2O
[ dont forget your sig figs guys! ]
need more practice??
Percent Yield Practice Problems
1. A student adds 200.0g of C7H6O3 to an excess of C4H6O3, this produces C9H8O4 and C2H4O2. Calculate the percent yield if 231 g of aspirin (C9H8O4) is produced.
C7H6O3 + C4H6O3 à C9H8O4 + C2H4O2
2. According to the following equation, Calculate the percentage yield if 550.0 g of toluene ()added to an excess of nitric acid () provides 305 g of the p-nitrotoluene product.
C7H8 + HNO3 à C7H7NO2 = H2O
3. Quicklime, CaO, can be prepared by roasting limestone, CaCO3, according to the chemical equation below. When 2.00 x 103 g of CaCO3 are heated, the actual yield of CaO is 1.50 x 103 g. What is the percentage yield?
CaCO3 à CaO + CO2
Answers:
1. ≈90%
2. 37.2%
3. 93.8%
SOMETHING YOU CAN WATCH:
http://www.youtube.com/watch?v=TKNxdL7DN1I&feature=player_embeddedhttp://www.youtube.com/watch?v=lDvTIgUi56I&feature=player_embedded
http://www.youtube.com/watch?v=UZsfANe1ayI&feature=player_embedded
http://www.youtube.com/watch?v=_tZm03nnWrA&feature=player_embedded
http://www.youtube.com/watch?v=ClTbd0qTdWw&feature=player_embedded
^ ALL OF THOSE VIDS CAN BE FOUND IN ONE WEBSITE. HOW NICE IS THAT?
JUST CLICK HERE. EASY AS THAT. YOUR WELCOME AND ENJOY (:
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JOKE OF THE DAY! (:
Q: If H2O is the formula for water, what is the formula for ice?
A: H2O cubed.
HA-HA-HA
Im so funny.
I just LOLed at your joke, and I am going to tell it to all of my sophomore chemistry students today! =)
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